Learning Curve

T_{n} = T_{1} n^{b}, b = \frac{lo g r}{lo g 2}

Each doubling of cumulative units multiplies unit time by r (e.g. 90% curve: r=0.9). Use for repetitive formwork, pile driving, precast cycles. Total time is the sum, or integrate for large n.

$T 1$: Time for the first unit
$r$: Learning rate (decimal)
$n$: Unit number

Step-by-step solved example

T1=10 h, 90% curve. Time of the 8th unit? (8=2³)

Repetitive cycles on the network get faster: Tn = T1 n^b.

1. b
log0.9/log2= −0.1522.
2. T8
Three doublings: 10×0.9³=7.29 h.

Answer: T8 = 7.29 h

10 practice questions

0/10 correct

1.80% curve is

2.r=1 means

3.Unit 4 on a 90% curve from T1 is

4.b is negative because

5.Crew change / layoff often

6.T1=8 h, 80% , n=2: T2=

7.Cumulative time for n units is not n×Tn because

8.log r / log 2 for r=0.9 is nearest

9.Prefabrication that repeats 100 times is a good

10.A 70% curve from 12 h: 8th unit (3 doublings) is