Step-by-step solved example
γ = 150 pcf, fluid head h = 8 ft (uncapped). p?
1. Hydrostatic
p = 150×8 = 1,200 psf.
2. Note
Compare with ACI pmax; use the smaller for design of wall ties.
Answer: 1,200 psf
γ = 150 pcf, fluid head h = 8 ft (uncapped). p?
1. Hydrostatic
p = 150×8 = 1,200 psf.
2. Note
Compare with ACI pmax; use the smaller for design of wall ties.
Answer: 1,200 psf
1.If ACI pmax = 2000 psf and γh = 1200 psf, design p =
2.Faster pour rate tends to
3.Higher concrete temperature tends to
4.γ = 23.5 kN/m³, h = 2.0 m. p =
5.Vibration of the lift
6.Slab formwork (bottom) is designed for
7.150 pcf × 1 ft =
8.Retarding admixture
9.Tie load ≈ p × tributary area of the tie.
10.Lightweight concrete (smaller γ) gives