Step-by-step solved example
Cumulative % retained No.4 to No.100: 2, 15, 40, 70, 90, 97. FM?
1. Sum
2+15+40+70+90+97=314.
2. FM
314/100=3.14 (slightly coarse).
Answer: FM = 3.14
Cumulative % retained No.4 to No.100: 2, 15, 40, 70, 90, 97. FM?
1. Sum
2+15+40+70+90+97=314.
2. FM
314/100=3.14 (slightly coarse).
Answer: FM = 3.14
1.FM is dimensionless
2.Pan percent passing is not
3.Coarser sand has
4.If every cumulative is 0, FM=
5.Uniformity coefficient Cu is
6.ASTM C33 concrete sand FM typically
7.Six sieves summing to 270 give FM=
8.Replacing coarse sand with fine sand at the same w/c
9.Gap-graded agg can still have a numeric FM but
10.No. 200 sieve is about