Step-by-step solved example
Pendulum 20 kg, h1=1.2 m, h2=0.4 m. Absorbed energy?
1. Δh
1.2−0.4=0.8 m.
2. E
20×9.81×0.8=157 J.
Answer: 157 J
Pendulum 20 kg, h1=1.2 m, h2=0.4 m. Absorbed energy?
1. Δh
1.2−0.4=0.8 m.
2. E
20×9.81×0.8=157 J.
Answer: 157 J
1.A higher Charpy energy means
2.DBTT is a concern for
3.Austenitic stainless (FCC) typically shows
4.Notch-sensitive materials have
5.If h2=h1, absorbed energy is
6.ft·lb to J: multiply by
7.Upper-shelf energy is
8.Welding may raise DBTT in the HAZ because
9.Charpy is not a design stress; it is
10.m=10 kg, Δh=0.5 m: E≈