Step-by-step solved example
Evaluate ∫ from 0 to 2 of x² dx.
1. Antiderivative
∫ x² dx = x³/3.
2. Evaluate bounds
[x³/3]_0^2 = 8/3 − 0 = 8/3 ≈ 2.667.
Answer: 8/3
Evaluate ∫ from 0 to 2 of x² dx.
1. Antiderivative
∫ x² dx = x³/3.
2. Evaluate bounds
[x³/3]_0^2 = 8/3 − 0 = 8/3 ≈ 2.667.
Answer: 8/3
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