Step-by-step solved example
x̄ = 100, σ = 15, n = 25. Construct the 95% CI for μ.
1. Standard error
σ/√n = 15/5 = 3.
2. Margin and interval
z_{0.025} = 1.96. ME = 5.88. CI: 100 ± 5.88 → (94.12, 105.88).
Answer: 94.1 to 105.9
x̄ = 100, σ = 15, n = 25. Construct the 95% CI for μ.
1. Standard error
σ/√n = 15/5 = 3.
2. Margin and interval
z_{0.025} = 1.96. ME = 5.88. CI: 100 ± 5.88 → (94.12, 105.88).
Answer: 94.1 to 105.9
1.σ = 20, n = 25. SE = σ/√n equals
2.For a 95% two-sided interval, z_{α/2} ≈
3.Increasing n makes the CI
4.x̄ = 50, z = 2, σ = 10, n = 16. Margin of error is
5.A 90% two-sided z is nearest
6.99% two-sided z_{α/2} is nearest
7.Quadrupling n multiplies SE by
8.When σ is known, a mean CI uses the
9.The half-width of the interval is
10.A 95% CI means that