Step-by-step solved example
W=300 kN/m, δ=25°, Pa=80 kN/m, Pp=0. FS sliding?
1. Resist
W tanδ=300 tan25°=140 kN/m.
2. FS
FS=140/80=1.75.
Answer: 1.75
W=300 kN/m, δ=25°, Pa=80 kN/m, Pp=0. FS sliding?
1. Resist
W tanδ=300 tan25°=140 kN/m.
2. FS
FS=140/80=1.75.
Answer: 1.75
1.Typical minimum sliding FS is about
2.Overturning FS uses
3.A wider heel increases W and
4.Base δ is often taken as
5.Passive in front of the toe should be
6.If Pa doubles and W is unchanged, sliding FS
7.Bearing check uses
8.A key at the base
9.Horizontal seismic (Mononobe–Okabe) typically
10.Units: W tanδ and Pa must both be