Step-by-step solved example
LL = 62, PL = 28, natural w = 40. Find PI and LI.
1. PI
PI = 62 − 28 = 34.
2. LI
LI = (40 − 28)/34 = 12/34 = 0.353.
Answer: PI = 34, LI = 0.35
LL = 62, PL = 28, natural w = 40. Find PI and LI.
1. PI
PI = 62 − 28 = 34.
2. LI
LI = (40 − 28)/34 = 12/34 = 0.353.
Answer: PI = 34, LI = 0.35
1.LL = 55, PL = 25. PI =
2.A soil with w = PL has LI =
3.A-line on the plasticity chart is
4.USCS: a fine soil above the A-line with LL = 60 is
5.w = 50, PL = 20, PI = 40. LI =
6.If natural w exceeds LL, the soil is
7.Shrinkage limit SL is the water content where
8.Nonplastic silt (NP) has
9.Activity = PI / (clay fraction). High activity (> 1.25) suggests
10.Liquidity index of a soil at the liquid limit is