Step-by-step solved example
σx=80 MPa, σy=0, τ=30 MPa. σ_v?
1. Plug in
σ_v=√(80²−0+0+3×900)=√(6400+2700)=√9100=95.4 MPa.
2. Compare
Yield if 95.4 ≥ Sy.
Answer: σ_v ≈ 95 MPa
σx=80 MPa, σy=0, τ=30 MPa. σ_v?
1. Plug in
σ_v=√(80²−0+0+3×900)=√(6400+2700)=√9100=95.4 MPa.
2. Compare
Yield if 95.4 ≥ Sy.
Answer: σ_v ≈ 95 MPa
1.Pure shear τ (σx=σy=0): σ_v =
2.Uniaxial σ: σ_v =
3.Ductile yield (von Mises) vs brittle (max-normal) — FE uses
4.σx=σy=σ, τ=0: σ_v =
5.FS = Sy / σ_v for
6.Plane stress σz=0 is already built into
7.Hydrostatic stress (σ,σ,σ) has σ_v
8.If σ_v=180 and Sy=360, FS=
9.Principal-stress form is
10.Compared with Tresca at the same Sy, von Mises