Step-by-step solved example
σx=40, σy=−20, τ=0 MPa. τ_max (absolute, plane stress)?
1. Principals
σ1=40, σ2=−20, σ3=0.
2. Max shear
(σ1−σ2)/2=30 MPa (larger than 20 or 10).
Answer: τ_max = 30 MPa
σx=40, σy=−20, τ=0 MPa. τ_max (absolute, plane stress)?
1. Principals
σ1=40, σ2=−20, σ3=0.
2. Max shear
(σ1−σ2)/2=30 MPa (larger than 20 or 10).
Answer: τ_max = 30 MPa
1.In-plane Mohr radius is
2.Tresca yield in uniaxial tension at Sy means τ_max =
3.Pure shear τ yields (Tresca) when τ =
4.Center of Mohr’s circle is
5.If σx=σy and τ=0, in-plane τ_max is
6.Principal orientation tan 2θp =
7.Absolute max shear in plane stress can use σ=0 as a principal
8.σx=100, σy=0, τ=0: R =
9.Sign convention on FE Mohr: +τ
10.Tresca hexagon vs von Mises circle in π-plane: Tresca is