Step-by-step solved example
Steel with E = 200 GPa and ε = 0.0010. Find σ.
1. Hooke
σ = Eε = (200×10⁹)(0.0010) = 200×10⁶ Pa.
2. Check range
200 MPa is below typical steel yield (~250–350 MPa), so the elastic assumption is reasonable.
Answer: 200 MPa
Steel with E = 200 GPa and ε = 0.0010. Find σ.
1. Hooke
σ = Eε = (200×10⁹)(0.0010) = 200×10⁶ Pa.
2. Check range
200 MPa is below typical steel yield (~250–350 MPa), so the elastic assumption is reasonable.
Answer: 200 MPa
1.E = 200 GPa, ε = 5.0×10⁻⁴. σ =
2.σ = 150 MPa, E = 200 GPa. ε =
3.Hooke’s law holds
4.E of ordinary concrete is typically about
5.Strain ε is
6.E is the slope of
7.Aluminum E is about
8.σ = Eε assumes
9.ε = 0.0020, E = 70 GPa. σ =
10.Beyond yield, uniaxial Hooke’s law