Step-by-step solved example
V=500 m³, X=3000 mg/L = 3.0 kg/m³, wasted solids 150 kg/d (neglect effluent X). θc?
1. Mass in reactor
VX=500×3=1500 kg.
2. θc
θc=1500/150=10 d.
Answer: 10 d
V=500 m³, X=3000 mg/L = 3.0 kg/m³, wasted solids 150 kg/d (neglect effluent X). θc?
1. Mass in reactor
VX=500×3=1500 kg.
2. θc
θc=1500/150=10 d.
Answer: 10 d
1.θc is also called
2.If wasting increases, θc
3.HRT t = V/Q is
4.Neglecting Xe, θc ≈
5.Longer θc generally
6.X is typically
7.Units: VX in kg, waste in kg/d → θc in
8.If Qe Xe is not neglected in a poorly settling plant, θc
9.Typical conventional activated-sludge θc is on the order of
10.θc and F/M are