Step-by-step solved example
Q=9 m³/s in a 3 m wide rectangle. yc?
1. q
q=9/3=3.0 m²/s.
2. yc
(9/9.81)^{1/3}=0.917^{1/3}≈0.97 m.
Answer: yc ≈ 0.97 m
Q=9 m³/s in a 3 m wide rectangle. yc?
1. q
q=9/3=3.0 m²/s.
2. yc
(9/9.81)^{1/3}=0.917^{1/3}≈0.97 m.
Answer: yc ≈ 0.97 m
1.Fr>1 is
2.Emin for a rectangle is
3.A wide channel approximates
4.If Q doubles in a rectangle, yc scales by
5.Triangle/trapezoid yc needs
6.Control at a free overfall is
7.q=4 m²/s, yc nearest
8.Mild slope GVF approaching a steep slope passes
9.c_wave = √(gy) so Fr=V/c
10.g in USCS for yc=(q²/g)^{1/3} is