Step-by-step solved example
Wheel r=0.4 m, a_G=2 m/s², no slip. α?
1. Kinematic link
a=rα → α=2/0.4=5 rad/s².
2. IC
Instantaneous center at the ground contact.
Answer: α = 5 rad/s²
Wheel r=0.4 m, a_G=2 m/s², no slip. α?
1. Kinematic link
a=rα → α=2/0.4=5 rad/s².
2. IC
Instantaneous center at the ground contact.
Answer: α = 5 rad/s²
1.If the wheel slips, v and rω are
2.Work of static friction in pure rolling is
3.I about contact C by parallel axis is
4.v_G=8 m/s, r=0.5 m, no slip: ω =
5.Required friction for a disk accelerated by M at the hub depends on
6.Hoop I=mR² rolling down a height h: v =
7.Sphere I=2/5 mR² is faster than a hoop because
8.Point at the top of a rolling wheel has speed
9.Impending slip uses
10.a_G of rolling down θ (no slip, disk ½mR²) is