Step-by-step solved example
Measured slope distance 150.00 ft at +8°00' vertical angle. Find H.
1. Cosine
cos 8° = 0.990268.
2. Horizontal
H = 150.00 × 0.99027 = 148.54 ft.
Answer: H = 148.54 ft
Measured slope distance 150.00 ft at +8°00' vertical angle. Find H.
1. Cosine
cos 8° = 0.990268.
2. Horizontal
H = 150.00 × 0.99027 = 148.54 ft.
Answer: H = 148.54 ft
1.S = 100.00 m, θ = 0°. H =
2.S = 80.00 ft, θ = 60°. H =
3.Zenith angle z = 90° means the sight is
4.H = S sin z. If z = 80°, S = 200 m, H is nearest
5.A 2% grade is a vertical angle nearest
6.Using S instead of H in a traverse will
7.θ = −12° (downhill) vs +12° for the same S. H is
8.S = 50.000 m, θ = 5.00°. Correction S − H is nearest
9.EDM slope reduction also needs
10.Percent slope s% related to θ by